1. Calculate the stoichiometric air/fuel ratio by mass and by volume for the following fuels. a) Octane ($C_8H_{18}$) b) Ethyl Alcohol ($C_2H_6O$) For the purpose of the "by volume" analysis, you can consider the fuels to be gasses/vapours.
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a) Octane (C8H18): 1 mole of octane (C8H18) requires 12.5 moles of oxygen (O2) for complete combustion. The molecular weight of octane (C8H18) = 114 g/mol The molecular weight of oxygen (O2) = 32 g/mol Therefore, the mass ratio of air to octane is: (12.5 * 32) / Show more…
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