00:01
To solve this particular question, we need to find the pooled standard deviation first, which can be formulated as n1 minus n times s1 square plus n2 minus 1 times h2 square upon n1 plus n2 minus 2, right, where n1 is the number of the sample space of 1 and s1 is the standard deviation, right.
00:21
So, just upon substituting the values, let's say n1 is given to us as 50, 50 minus 1 and the standard deviation corresponding to it is 0 .37 whole square, right, plus we have 55 minus 1 times the standard deviation corresponding to it is 0 .41 whole square upon n1 plus n2 minus 2, right.
00:42
So, this is 50 n1, 55 is n2 minus 2, right.
00:47
So, the standard pooled deviation can be calculated as 0 .391.
00:52
Now, we know that the standard error can be calculated using the formula of the standard pooled deviation times root over of reciprocals of the sample spaces addition, right.
01:03
So, this is 1 upon n1 plus 1 upon n2...