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1. Calculate the theoretical yield of the product formed when exactly 10.0 grams of bromobenzene, and 10.0 grams of magnesium are used to generate the Grignard reagent which in turn is then reacted with 10.0 grams of methyl benzoate to produce triphenylmethanol. 2 [phenylmagnesiumbromide] + [methyl benzoate] --1. Ether / 2. H3O+, H2O--> [triphenylmethanol] phenylmagnesiumbromide methyl benzoate triphenylmethanol 2. During the Grignard reagent preparation, the reaction mixture is diluted by adding ether. This helps prevent an unwanted dimerization reaction in which two molecules of bromobenzene yield biphenyl (structure below). Realizing that bromobenzene and phenylmagnesium bromide are both present in the reaction pot at the same time, suggest a simple mechanism that shows how biphenyl could be forming. [biphenyl] biphenyl 

          1. Calculate the theoretical yield of the product formed when exactly 10.0 grams of bromobenzene, and 10.0 grams of magnesium are used to generate the Grignard reagent which in turn is then reacted with 10.0 grams of methyl benzoate to produce triphenylmethanol.

2 [phenylmagnesiumbromide] + [methyl benzoate] --1. Ether / 2. H3O+, H2O--> [triphenylmethanol]

phenylmagnesiumbromide methyl benzoate triphenylmethanol

2. During the Grignard reagent preparation, the reaction mixture is diluted by adding ether. This helps prevent an unwanted dimerization reaction in which two molecules of bromobenzene yield biphenyl (structure below). Realizing that bromobenzene and phenylmagnesium bromide are both present in the reaction pot at the same time, suggest a simple mechanism that shows how biphenyl could be forming.

[biphenyl]
biphenyl
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1. Calculate the theoretical yield of the product formed when exactly 10.0 grams of bromobenzene, and 10.0 grams of magnesium are used to generate the Grignard reagent which in turn is then reacted with 10.0 grams of methyl benzoate to produce triphenylmethanol. 2 [phenylmagnesiumbromide] + [methyl benzoate] –1. Ether / 2. H3O+, H2O–> [triphenylmethanol] phenylmagnesiumbromide methyl benzoate triphenylmethanol 2. During the Grignard reagent preparation, the reaction mixture is diluted by adding ether. This helps prevent an unwanted dimerization reaction in which two molecules of bromobenzene yield biphenyl (structure below). Realizing that bromobenzene and phenylmagnesium bromide are both present in the reaction pot at the same time, suggest a simple mechanism that shows how biphenyl could be forming. [biphenyl] biphenyl

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Calculate the theoretical yield of the product formed when exactly 10.0 grams of bromobenzene and 10.0 grams of magnesium are used to generate the Grignard reagent, which in turn then reacts with 10.0 grams of methyl benzoate to produce triphenylmethanol. OH Mg-Br Ether 2H2O phenylmagnesiumbromide methyl benzoate triphenylmethanol During the Grignard reagent preparation, the reaction mixture is diluted by adding ether. This helps prevent an unwanted dimerization reaction in which two molecules of bromobenzene yield biphenyl (structure below). Realizing that bromobenzene and phenylmagnesium bromide are both present in the reaction pot at the same time, suggest a simple mechanism that shows how biphenyl could be forming: biphenyl
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please calculate the theoretical yield of triphenylmethanol from 10 ml of bromobenzene reacting with 2 moles of Grignard reagent reacting with 1 mole of the ester methyl benzoate. Molecular weight of bromobenzene = 157 g/mol and the density is 1.491 g/ml. molecular weight of methyl benzoate = 136.16 g/mol, and the density is 1.09 g/ml. molecular weight of triphenylmethanol = 260.34 g/mol. Please show all steps and follow proper stoichiometry.

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please determine the limiting reagent in the synthesis of triphenylmethanol from bromobenzene, reacting with 2 moles of Grignard Reagent with one mole of ester (methyl benzoate)? please calculate the theoretical yield of triphenylmethanol from 10 mL of bromobenzene and then follow with the determination of the limiting reagent calculation.

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Transcript

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00:01 Dear students, 10 gram of bromobenzine is allowed to react with 10 gram of magnesium to produce phenyl magnesium bromide and the resulted frenile magnesium bromide is allowed to react with 10 gram of methylbenzoate and what is the amount of the final product formed that is trifenile methanol.
00:19 This is our question.
00:21 Now for this we need molar masses of the substances bromobenzine.
00:25 It is 157.
00:28 Molar masses it is 157 then magnesium we know 24 gram per mole and methyl benzoate methyl benzoate is 136 gram per mole so these are the molar masses of the substances now we see here first we'll find out the limiting reactant between bromobenzene and magnesium for the formation of phenyl magnesium bromide then we'll find out the limiting reactant again between philine magnesium bromide and methylbenzoate and from that value we'll find out the mass of the product so it is a three -step reaction problem so first step finding the limiting reactant between bromobenzion and magnesium as per the equation we know one 57 gram of bromium bromobenzene needs 24 gram of magnesium.
01:46 Therefore, 10 gram of bromobenzion will need 24 plus 10 divided by 157, about 4 .21 gram of magnesium.
02:02 But magnesium is 10 gram, therefore magnesium is excess.
02:07 Magnesium is excess therefore here in the first step bromob engine is the limiting reactant now in the second step we will calculate how much of phenyl magnesium bromide or gregnard reagent will form so here as for the equation because bromob engine is the limiting reactant therefore 157 gram of bromob engine will write here will relate 157 gram of bromobenzene results into 181 gram of nile magnesium bromide.
03:05 Therefore we have 10 gram of benzene, so it will result into 181 multiplied by 10 divided by 157 which is equal to it is 11 .5 gram of phenyl magnesium bromide will form.
03:23 Now in the third step we'll see phenyl magnesium bromide from the equation it is clear phenyl magnesium bromide one mole of phenyl magnesium bromide produces one mole of trifenile methanol.
03:43 So here phenyl magnesium bromide molar mass as we have seen here it is a very, it is a is 181 gram.
03:54 So 181 gram reacts with methylbenzoid.
03:58 How much? methylvanjord, 1306 gram.
04:02 Again, we have to find out here the limiting reactant.
04:07 So 181 gram of phenyl magnesium bromide reacts with how much here? 136...
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