Question

Calculate the total change in entropy Δ? if ?1=4.55 kg of water at ?1=29.5 ∘C is mixed with ?2=7.75 kg of water at ?2=79.5 ∘C. The specific heat of water is 4186 J/(kg·K).

          Calculate the total change in entropy  Δ?  if  ?1=4.55 kg  of water at  ?1=29.5 ∘C  is mixed with  ?2=7.75 kg  of water at ?2=79.5 ∘C.  The specific heat of water is  4186 J/(kg·K).
        

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Thermal Physics : Kinetic Theory, Thermodynamics and Statistical Mechanics
Thermal Physics : Kinetic Theory, Thermodynamics and Statistical Mechanics
S.C. Garg, R.M. Bansal, C.K. Ghosh 2nd Edition
Chapter 7
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Calculate the total change in entropy Δ? if ?1=4.55 kg of water at ?1=29.5 ∘C is mixed with ?2=7.75 kg of water at ?2=79.5 ∘C. The specific heat of water is 4186 J/(kg·K).
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Transcript

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00:01 Hello, here we have to determine the total change in entropy, delta s, as we mix m1 of 4 .55 kg of water at 29 .5 c with m2, which is 7 .75 kg of water at 79 .5 c.
00:23 Let's do this.
00:24 First, we have to find the final temperature.
00:28 Let's do this.
00:29 Here, specific heat capacity of water m1 t final minus t1 equals to specific heat capacity of water m2 times t2 minus t final.
00:48 So now let's calculate t final.
00:51 Let's basically solve this.
00:55 Let's find t final.
02:00 This is 61 degrees c.
02:03 And now let's determine change in entropy.
02:07 That's delta s1 plus delta s2.
02:12 And here, this change in entropy can be found as following.
02:17 Delta s in principle is an integral from some temperature t initial to t final of cv over t dt.
02:33 Which is basically specific heat capacity of water times natural logarithm of t final over t initial.
02:50 And here this t is incalculated...
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