00:01
Given the momentum of electron p as 1 m .a .v.
00:05
By c.
00:08
Now, in the first question, we have to calculate the total energy of the given relativistic electron.
00:14
Total energy is given by the expression.
00:17
Total energy of a relativistic electron is given by e equals root of p square c square plus m0 square c raised to 4.
00:29
Here c is the speed of light and m0 is the rest mass energy of electron which is given by 0 .511 mev by c square.
00:41
Therefore e is equals to p square that is 1 square root of 1 square plus 0 .511 square.
00:54
This will give a value of 1 .123 mev.
01:00
Therefore the total energy of the given relativistic.
01:03
Electron is calculated as 1 .123 m .a .v.
01:09
Now let us move on to subpart the second question.
01:12
Question number two...