Calculate the values of three currents in the circuit shown in Fig. 1, assume Vbe =0V + Vcc = 10 V RB = 1 M? RC = 2 k? ? = 100 RE = 1 k? b. IC = 0.0095 mA, IB = 0.95 mA, IE = 0.959 mA d. IC = 0.0095 mA, IB = 0.91 mA, IE = 0.919 mA c. IC = 0.0091 mA, IB = 0.95 mA, IE = 0.959 mA a. IC = 0.0091 mA, IB = 0.91 mA, IE = 0.919 mA
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We are given Vcc (the supply voltage) as 10V, Rc (the collector resistor) as 2kΩ, Rg (the base resistor) as 1MΩ, IB (the base current) as 100μA, IE (the emitter current) as 1.9mA, and IC (the collector current) as 0.0095mA. Note that there seems to be a mistake in Show more…
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