00:01
In this question we are given wavelength of two electrons.
00:04
The first electron wavelength is 1 x 10 raised to the power 2 nanometer.
00:11
And the wavelength of second electron is 1 nanometer.
00:22
Now here we have to identify the velocity of both the electron v1 and v2.
00:31
As we know, we know the relation between wavelength and velocity of electron.
00:41
That is lambda.
00:44
That is de broglie wavelength.
00:46
Lambda is equal to h upon mb.
00:52
Here h is, lambda represent the wavelength and h is planck constant.
01:07
And the value of that constant is 6 .62 x 10 raised to the power minus 34.
01:18
And here, another, here m represent the mass joule per second.
01:26
34 joule per second.
01:28
And here we know, this is m represent the mass.
01:35
And we know mass of electron is 9 .1 x 10 raised to the power minus 31 kc...
