00:01
So to solve for this, just remember thatularity m is equivalent to the moles of a solute.
00:09
That's our numerator over the volume of the solution, which should be in terms of liters.
00:16
Okay, so we know that molarity is 4 .4m.
00:20
That means 4 .4 moles per liter.
00:25
That's m.
00:26
And then for the numerator, we have the moment.
00:30
Of salute but instead of moles we are given 175 grams of our solute so that means that's right here 175 grams of na and then convert this to number of moles will need its molar mass molar mass of nan03 will be it's right here 80 84 .99 grams is 84 .99 grams it's this is the molar mass of sodium nitrate, okay? for every mole of sodium nitrate, okay? that means our unit for the numerator is already in terms of moles, and then the volume of the solution is our unknown.
01:19
So i'll just write that as v, okay? so arranging this, probably for v.
01:26
V therefore is equivalent to 175 divided by, by 84 .99, further divided by 4 .4.
01:36
So that means we'll get 0 .468...