Calculate these masses. (a) What is the mass of 6.00 $\mathrm{cm}^{3}$ of mercury, density $=13.5939 \mathrm{g} / \mathrm{cm}^{3} ?$ (b) What is the mass of 25.0 $\mathrm{mL}$ octane, density $=0.702 \mathrm{g} / \mathrm{cm}^{3} ?$
Added by Cheryl C.
Step 1
00 cm$^{3}$ and the density of mercury as 13.5939 g/cm$^{3}$. We can use the formula: mass = volume x density. Substituting the given values, we get: mass = 6.00 cm$^{3}$ x 13.5939 g/cm$^{3}$ Show more…
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