Calculate the pH of 540 mL of a 0.454 M solution of hydrofluoric acid before and after the addition of 7.24Ă—10^-2 mol of sodium fluoride. pH before addition = pH after addition =
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454 M solution of hydrofluoric acid before the addition of sodium fluoride. Given: - Initial concentration of HF = 0.454 M - Volume of solution = 540 mL = 0.54 L - Ka value of HF = 6.6 x 10^-4 Show more…
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