Calculations calculate the unknown molarity of hydrochloric...

Calculations: Calculate the unknown molarity of hydrochloric acid using dimensional analysis. Enter numerical values below: Molarity of NaOH used: 0.145 M The volume of HCl pipetted out for the titration: 20 mL The volume of NaOH dispensed at the equivalence point: 10.4 mL Molarity of HCl calculation:

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Transcript

00:09 I'll do my best to figure this one out, but it's very hard to read.

00:11 So we have a balanced chemical equation that we're given, and it doesn't say anything.

00:32 It just says unknown, so i'm going to write.

00:43 The molar concentration of sodium hydroxide, we're told to use 0 .1482.

01:07 Titration of hcl.

01:22 And it looks like i have two trials.

01:32 And i have 16 .92 milliliters and 16 .9 .9.

01:39 Milliliters.

01:41 And this is my final volume.

01:49 My volume of n -a -o -h dispensed will be 16 .92 and 16 .99.

02:10 Then we need to calculate moles of n -a -o -h, and then we need to calculate moles of acid, calculations, moles of h -dispensed, molar concentration sample one, sample two.

02:49 Volume of acid is 25 .0 milliliters.

03:24 Okay, i think we've got it.

03:31 So the first thing we're going to figure out is the moles of n -a -o -h.

03:36 And for each of these, it's going to equal the volume, divided by a thousand times 0 .1482 moles per liter.

03:59 So my first equation, my first calculation will be 0 .01692 liters times 0 .1482 moles per liter.

04:21 This answer will go right there, and that will be 0 .00250 .08 moles...