Question

X2(g) + Y2(g) ? 2 XY(g) ?H = -180 kJ X2(g) + 3 Z2(g) ? 2 XZ3(g) ?H = 92 kJ 2 Z2(g) + Y2(g) ? 2 Z2Y(g) ?H = -486 kJ According to the reactions given above calculate the heat of reaction under constant volume at 298 K for the following reaction. 4 XZ3(g) + 5 Y2(g) ? 4 XY(g) + 6 Z2Y(g)

          X2(g) + Y2(g) ? 2 XY(g) ?H = -180 kJ
X2(g) + 3 Z2(g) ? 2 XZ3(g) ?H = 92 kJ
2 Z2(g) + Y2(g) ? 2 Z2Y(g) ?H = -486 kJ
According to the reactions given above calculate the heat of reaction under constant volume at 298 K for the following reaction.
4 XZ3(g) + 5 Y2(g) ? 4 XY(g) + 6 Z2Y(g)

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X2(g) + Y2(g) ? 2 XY(g) ?H = -180 kJ
X2(g) + 3 Z2(g) ? 2 XZ3(g) ?H = 92 kJ
2 Z2(g) + Y2(g) ? 2 Z2Y(g) ?H = -486 kJ
According to the reactions given above calculate the heat of reaction under constant volume at 298 K for the following reaction.
4 XZ3(g) + 5 Y2(g) ? 4 XY(g) + 6 Z2Y(g)

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Physical Chemistry for IIT JEE

Atul Singha 1st Edition

Chapter 4

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Solved by Expert David Collins

06/08/2023

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