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Hello everyone.
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Here in this question it is given that mass of metal 89 .2 at initial temperature 98 degrees celsius or 371 .15 kelvin dissolved in water of mass 147 .5 grams at initial temperature t1 22 .5 degrees celsius or 295 .65 kelvin and final temperature t2 .28.
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0 .2 degrees celsius or 301 .35 kelvin have specific heat of 4 .181 jule per gram kelvin and we have to determine the specific heat of metal.
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Let us first determine heat of water and we know that heat q is equal to m c del t where m is the mark c is the specific heat and dlt is the change in temperature.
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Let's place the values and find the value of heat for water.
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The mass of water used in solution is 147 .5 grams.
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Multiply to specific heat, 4 .181.
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And change in temperature is final temperature, that is 301 .35.
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35 kelvin subtracted by initial temperature that is 295 .65.
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This is equal to 616 .69 multiplied to 5 .7 is equal to 3 ,515 .17 .17 .17 .75.
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So the heat of water is 3 ,515 .17 .17.
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So we will use this value of heat of water to determine the specific heat of metal...