Can someone explain to me in absolute detail how, in this question at stage 1-2, for a simple Rankine cycle, the specific volume (VL) is equal to 0.001007 m^3/kg? If I can find it from the steam tables, can someone show me how exactly?
Determine the Rankine for a simple Rankine Cycle which uses steam as the working substance. The condenser pressure is 0.007 MN/m^2 and the boiler pressure is 2 MN/m^2. Steam leaves the boiler as a saturated vapor, and all processes may be assumed to be reversible.
Solution:
psat = 0.007 MN/m^2
VL = 0.001007 m^3/kg