00:01
Now we know that the torque will be equal to the distance multiplied by the perpendicular force that is being applied on the system.
00:10
Now the weight of the man is given to us as 800 newton and that of the sun is 200 newton.
00:16
Therefore from torque equilibrium we have 800 newton that is the weight of the man multiplied by its distance from the pivot point equal to 200 newton weight of the child multiplied by the 3 metres of distance that it is away from the balance point.
00:30
This gives us the x distance to be equal to, which will be equal to 0 .75 meters.
00:42
Therefore, the man needs to be placed at a distance of 0 .75 meters from the balance point in order to balance the seesaw.
00:49
According to that, option a will be the correct answer.
00:55
In our next section, we will ask that if a bridge who's resting on two pillars has any torque acting on it.
01:01
Now the torque acting due to the individual forces won't be zero, about a, chosen point, except the acting point of force.
01:12
However, for rotational equilibrium, the net torque will be 0...