00:01
So the vertical forces on m1 are nothing but the this port, that is the tension in the string acting upwards and the weight of the mass m1g acting downwards.
00:19
So these are the two vertical forces.
00:22
M1g is due to the due to its weight, that is due to the vibrational pool and t is generated due to it is attached to another mass m2 by a stream and that's why and the m2 is also i mean suspended like this so n2 g is acting here and due to this weight there is a tension actually so these are the two actually tensions vertically upward and n1g vertically downward, these are the two vertical forces acting on this m1 force.
01:05
Now for the second question, we know actually this displacement d is nothing but half 80 square.
01:14
So from this we get t is equal to d is one, sorry, we need a.
01:25
So it is actually 2 multiplied by b, that is 1 divided by 0 .5 .5.
01:32
Square because time it is given as 0 .52 so if we calculate it will be 7 .4 meter per second square 7 .4 meter per second square okay now what a third case how can we use so if let's say like in the first the first row of the table m1 m2 is having a higher mass so in that case the equation of motion of m2 will be what it will be m2 g minus t because tension is like this is equal to n2a and for mask m1 the equation of motion will be what it will be t minus m1 g equal to m1a so if we eliminate t from these two equations then g will come in terms of a as a multiplied by m1 plus m2 divided by m so by knowing the value of a and by knowing the value of m1 and m2 we can have the value of v okay and the last question it is given in table 2 actually there is no table 2 in the question it is only given i mean only table 1 is given so actually we will take the table 1 and table 1 we are having this you can see that 300 is m1, m2 is 50 gram.
03:17
So from here actually we can have the value of g by putting the values of, sorry, for the first row, 100 ,000 gram, 750 gram.
03:27
So from that if we put the value, we get g is equal to 1...