00:01
We know that line p is perpendicular to line q.
00:05
Line q has an equation y equals 3x plus 5.
00:09
And we also know that line p contains 0 .6 negative 5.
00:15
So part 1 asks us to find the slope of line q.
00:21
So line q is provided to us in slope intercept form, which you see off to the right here.
00:25
And the slope is whatever number is in the same position as m.
00:29
Slope represents rise over run.
00:32
So if we match that up with this equation here, our slope is just three.
00:39
Next, we are asked to find the slope of line p.
00:42
Because line p and line q are perpendicular to one another, by definition they must have slopes that are negative reciprocals of one another.
00:52
So negative version of positive 3 would be negative 3, and the reciprocal of 3 is 1 3.
00:58
So the slope of line 3 is negative 1 3.
01:03
The third part asks us to write an equation for line p in point slope form, which is off to the side here.
01:14
Y minus y1 equals m times x minus x1, where m is still your slope and where x1, y1 is just a point on that line...