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Can you please assist with Q3 Design Memo: You are tasked to design a 100000 metric tons per annum production plant of PX. The formation of PX is obtained from the folowing polymerisation reaction and also lead to the formation of wax (by-products). Oxygen is used as an initiator to this reaction at a concentration of 50 ppm by weight 2000C+OC (PX) Eq.1 6CH + O (CH2 Table 1: Boiling Points of comp Cemponents Ethylene Oxyprn PX Wax (Wax) Eq. 2 Table 2: Price of components [Cemponcets Ethyfene Osygre Way rice(Kands) Ouestion 1:Using the heuristic and impurity of the peocess based on the boiling point at the atmospheric pressur Question 2: Draw the block flow diagram of the process at level 2 (Input-Output level) and write the Mass Balance (MB) (write each process stream as a function of the conversion X of the limiting reactant). Question 3:Calculate the Economic Potontial (EP) at input-Output level using your results in question 2 and prices in Table 2. Plot the EP versus X and decide on the value of the required ronversion for your process to be financially sustainable (Justify). What is the value of the selectivity at the sustainable EP? Duestion 4:Using the conversion in question 3 finalise the MB at input-output level Componcnt Mass Flowrate-In, kg/h Ethylene Oxygen PX Wax Mass Flowrate-Out,kg/h Qwestiem 5 calculate the volume of a PFR reactor (in m) (no pressure drop, Isothermal reaction) to achieve the conversion obtained in Question 3 if the reaction rate for thermal initiation of ethylene is given by: T = k,C Eq. 3 Where the rate constant is k=8.210-exp [(84000+47P)] 8.3147 Eq. 4 Where, p 300MPa =500K Average te R = 8314 MPa.dm3/moLK here oxygen decomposed) Question 6: By plotting and looking at the Levenspiel Plot, do you PFR in question 5 (discuss)? NB: The assignment is due on Friday 28 April 2023 on Ulwazi

          Can you please assist with Q3
Design Memo: You are tasked to design a 100000 metric tons per annum production plant of PX. The formation of PX is obtained from the folowing polymerisation reaction and also lead to the formation of wax (by-products). Oxygen is used as an initiator to this reaction at a concentration of 50 ppm by weight 2000C+OC (PX) Eq.1
6CH + O  (CH2 Table 1: Boiling Points of comp Cemponents Ethylene Oxyprn PX Wax
(Wax)
Eq. 2
Table 2: Price of components
[Cemponcets Ethyfene Osygre Way
rice(Kands)
Ouestion 1:Using the heuristic
and impurity of the peocess based on the boiling point at the atmospheric pressur Question 2: Draw the block flow diagram of the process at level 2 (Input-Output level) and write the Mass Balance (MB) (write each process stream as a function of the conversion X of the limiting reactant). Question 3:Calculate the Economic Potontial (EP) at input-Output level using your results in question 2 and prices in Table 2. Plot the EP versus X and decide on the value of the required ronversion for your process to be financially sustainable (Justify). What is the value of the selectivity at the sustainable EP?
Duestion 4:Using the conversion in question 3 finalise the MB at input-output level
Componcnt Mass Flowrate-In, kg/h Ethylene Oxygen PX Wax
Mass Flowrate-Out,kg/h
Qwestiem 5 calculate the volume of a PFR reactor (in m) (no pressure drop, Isothermal reaction) to achieve the conversion obtained in Question 3 if the reaction rate for thermal initiation of ethylene is given by: T = k,C Eq. 3 Where the rate constant is k=8.210-exp [(84000+47P)] 8.3147 Eq. 4
Where, p  300MPa =500K Average te R = 8314 MPa.dm3/moLK
here oxygen decomposed)
Question 6: By plotting and looking at the Levenspiel Plot, do you PFR in question 5 (discuss)?
NB: The assignment is due on Friday 28 April 2023 on Ulwazi
        
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can you please assist with q3 design memo you are tasked to design a 100000 metric tons per annum production plant of px the formation of px is obtained from the folowing polymerisation reac 09625

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Nivaldo Tro 2nd Edition
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Can you please assist with Q3 Design Memo: You are tasked to design a 100000 metric tons per annum production plant of PX. The formation of PX is obtained from the folowing polymerisation reaction and also lead to the formation of wax (by-products). Oxygen is used as an initiator to this reaction at a concentration of 50 ppm by weight 2000C+OC (PX) Eq.1 6CH + O (CH2 Table 1: Boiling Points of comp Cemponents Ethylene Oxyprn PX Wax (Wax) Eq. 2 Table 2: Price of components [Cemponcets Ethyfene Osygre Way rice(Kands) Ouestion 1:Using the heuristic and impurity of the peocess based on the boiling point at the atmospheric pressur Question 2: Draw the block flow diagram of the process at level 2 (Input-Output level) and write the Mass Balance (MB) (write each process stream as a function of the conversion X of the limiting reactant). Question 3:Calculate the Economic Potontial (EP) at input-Output level using your results in question 2 and prices in Table 2. Plot the EP versus X and decide on the value of the required ronversion for your process to be financially sustainable (Justify). What is the value of the selectivity at the sustainable EP? Duestion 4:Using the conversion in question 3 finalise the MB at input-output level Componcnt Mass Flowrate-In, kg/h Ethylene Oxygen PX Wax Mass Flowrate-Out,kg/h Qwestiem 5 calculate the volume of a PFR reactor (in m) (no pressure drop, Isothermal reaction) to achieve the conversion obtained in Question 3 if the reaction rate for thermal initiation of ethylene is given by: T = k,C Eq. 3 Where the rate constant is k=8.210-exp [(84000+47P)] 8.3147 Eq. 4 Where, p 300MPa =500K Average te R = 8314 MPa.dm3/moLK here oxygen decomposed) Question 6: By plotting and looking at the Levenspiel Plot, do you PFR in question 5 (discuss)? NB: The assignment is due on Friday 28 April 2023 on Ulwazi
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Transcript

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00:01 So we have the formula that is low k2 by k1 so this is equal to e by r 1 by t1 minus 1 by t2 so we will put the values k2 by 0 .1 so this is equal to 12500 divided by 1 .987 into 1 by 300 minus 1 by 350 so from here what we will get k2 is equal to 2 dm cube per mole second we will get this as k2 now we know t is equal to cao into xa divided by minus of ra so we know minus of ra is equal to k cao square into 1 minus xa m minus xa so from here what we will get ra is equal to 2 multiply with 16 .13 square multiply with 1 minus 0 .83 point 441 minus 0 .8 so from here what we will get this is equal to 274 .85 mole dm cube second now we know t is equal to cao multiply with xa divided by minus of ra so we will put these values so 16...
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