0:00
Hi.
00:02
For this question, we are giving the properties of a capacitor and we are told to find the capacitance.
00:11
So we know that c is equal to a times the permittivity in free space over the separation between the plates, where this permittivity is 8 .854 times 10 to the par minus 12.
00:32
And so the capital, capacitance and the unit of this, sorry, this should be farad per meter.
00:43
The capacitance therefore would be what 7 .86 times the permittivity, 8 .854 times 10 to the power minus 12.
00:56
Let me put the units so that i will verify the unit.
01:00
I just put meter squared.
01:05
8 .854 times 10 to the power minus 12 fared per meter.
01:14
All of that divided by the distance 7 .68 times 10 to the per minus 3 meter.
01:24
Yes, this will slash that.
01:27
And so we see that c will be equal to 9 .062 nanoparads to three decimal places...