00:01
Hi, i'm david and i'm here to have you answer your question.
00:04
Now let me bring up your question here.
00:07
In this question we discuss about the possum random variable.
00:10
Let me remind you that if we have the x followed by the possum with the rate equal to the lambda and then the probability x equal to k, it will equal to the n -2s -k, then p -bauer k, 1 minus p -bauer n minus k.
00:29
And in this question here, we are given that the car crossed a certain point on the highway with the poison process, with the lambda equal to the three per minute.
00:42
So if we call the x, it will equal to the number of the car crosses a certain point on the highway, and then x will follow by the possum with the lambda equal to the three cars per minute and then if il runs blindly across the highway one is a probability that he will be an incher if the amount of the time that it takes him to cross the growth will be s seconds so it means that we want to find that for the s equal to two first so means that we will have x equal to zero during two seconds and in the to -do discussion here, we need to know that.
01:39
Let me bring this one down a little.
01:43
We need to know that for one minute there will be average in the three cars.
01:50
And if we have the two seconds, it will, this one equal to the 60 seconds, how many cars we will have during the two seconds.
02:02
So to do that, we will turn the two times three.
02:05
Divided 60 so that equal to 1 over 10 so equal to 0 .1 count per second per two seconds therefore this one tells us that in the first part we're x equal followed by the possum with the lambda equal to the 0 .1 car per two seconds therefore we can be addition by formula here and then we can be a addition by formula here and then we get equal to e to the power minus 0 .1, 0 .1 power 0 ,000, different by 0 factorial.
02:44
And then we get the answer, it will equal to the e to the power minus 0 .1.
02:55
Then we get equal to the 0 .9 048...
