00:01
Okay, so i see that you need help with this problem.
00:03
And so the problem states the following.
00:06
Case managers and therapeutic foster home agencies completed assessment on at -risk youth who are clients of the agency.
00:13
They assessed for risky behaviors as well as mental health needs.
00:17
Higher scores indicate greater number of risky behaviors and greater need.
00:25
Conduct the following analysis on the assessment scores for each subscale.
00:30
Construct a group frequency distribution with interval wists of three for both risky behaviors and mental health needs.
00:38
Include frequencies, cumulative frequencies, percentages, and cumulative percentages.
00:44
What percentage of youth scored seven or higher on risky behavior? what percentage of youth scored six or lower on mental health? and what is the mean and median for both variables? so i pre -did this work, so i'm going to show you what i came up with.
01:05
Okay, so, oops.
01:08
Here are the tables, the frequency tables.
01:12
And so i have the constructed a group frequency distribution with interval with three for both risky behaviors and mental health needs.
01:22
So i have the frequencies of both.
01:24
I went from zero to two, three to five, six to eight, nine to eleven, and twelve to fourteen, then they went up to 12, but i had to do intervals of three.
01:34
So the only thing left is to, the only thing left is to, now what percentage of you scored seven or higher on risky behaviors? so for seven or higher, because you had to do intervals of three, seven is in between the six to eight so seven or higher i would have to include these numbers here so i would have to add up those numbers so i would have 12 plus 14 plus 33 plus 17 plus 26 plus 22 and that is 124 out of 155 and that is 80 percent then it says what percentage of you scored six or lower on mental health? so that would be this amount here.
02:49
So i would do 10 plus 22 plus 9 plus 3 plus 5 plus 1.
02:59
And that is 50 out of 165.
03:07
And that is about 30%.
03:10
Then it says what is the mean and median? of both variables.
03:16
So first of all, median is the easiest to find...