Question

Case studies showed that out of 10,351 convicts who escaped from U.S. prisons, only 7867 were recaptured (The Book of Odds by Shook and Shook, Signet). (a) Let $p$ represent the proportion of all escaped convicts who will eventually be recaptured. Find a point estimate for $p$. (b) Find a $99 \%$ confidence interval for $p$. Give a brief statement of the meaning of the confidence interval. (c) Is use of the normal approximation to the binomial justified in this problem? Explain. 

          Case studies showed that out of
10,351 convicts who escaped from U.S. prisons, only 7867 were recaptured
(The Book of Odds by Shook and Shook, Signet).
(a) Let $p$ represent the proportion of all escaped convicts who will eventually be recaptured. Find a point estimate for $p$.
(b) Find a $99 \%$ confidence interval for $p$. Give a brief statement of the meaning of the confidence interval.
(c)  Is use of the normal approximation to the binomial justified in this problem? Explain.
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Case studies showed that out of 10,351 convicts who escaped from U.S. prisons, only 7867 were recaptured (The Book of Odds by Shook and Shook, Signet). (a) Let $p$ represent the proportion of all escaped convicts who will eventually be recaptured. Find a point estimate for $p$. (b) Find a $99 \%$ confidence interval for $p$. Give a brief statement of the meaning of the confidence interval. (c) Is use of the normal approximation to the binomial justified in this problem? Explain.
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Transcript

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00:01 Hello students, the question that is given over here is that case showed that out of 10 ,351 come to escape from new york city, only 7 ,867 were recaptured.
00:19 So for the first part of the question, let t be the proportion of all the escaped risk to victim, verdict, escape, escape, convict.
00:32 And we'll actually write who will eventually be recaptured.
00:35 So the point estimate for p we have to find out.
00:38 For the point estimate of p is equal to 7 ,867 divided by 10 ,361.
00:47 The point estimate is 0 .7.
00:51 And the second part of the question we have to find out alpha value with 0 .01.
00:57 And z for 0 .995 is equal to 2 .87...
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