Câu 19: K?t qu? c?a phép chia hai phân th?c $\frac{2x+6}{(x+4)^2} \div \frac{3(x+3)}{x+4}$ là: $\circ \frac{1}{3(x+2)}$ $\circ \frac{2}{3}$ $\circ \frac{2}{3(x+4)}$ $\circ \frac{1}{3(x+4)}$ C?n xem l?i

          Câu 19:
K?t qu? c?a phép chia hai phân th?c
$\frac{2x+6}{(x+4)^2} \div \frac{3(x+3)}{x+4}$ là:
$\circ \frac{1}{3(x+2)}$
$\circ \frac{2}{3}$
$\circ \frac{2}{3(x+4)}$
$\circ \frac{1}{3(x+4)}$
C?n xem l?i

Câu 19:
K?t qu? c?a phép chia hai phân th?c
(2x+6)/((x+4)^2)÷(3(x+3))/(x+4) là:
∘(1)/(3(x+2))
∘(2)/(3)
∘(2)/(3(x+4))
∘(1)/(3(x+4))
C?n xem l?i

Added by Troy B.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Suzanne Harwood

Step 1

4 + h = 8.4 + h. Show more…

Show all steps

Thanks for your feedback!

CÃ¢u 19: Cáº§n xem Káº¿t quáº£ cá»§a phÃ©p chia hai pháº§n (hÆ°á»›ng 2+6.4+h) (+47)

Play audio

Feedback

Suzanne Harwood and 86 other subject Algebra educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Question

Câu 19: K?t qu? c?a phép chia hai phân th?c $\frac{2x+6}{(x+4)^2} \div \frac{3(x+3)}{x+4}$ là: $\circ \frac{1}{3(x+2)}$ $\circ \frac{2}{3}$ $\circ \frac{2}{3(x+4)}$ $\circ \frac{1}{3(x+4)}$ C?n xem l?i

Please give Ace some feedback