Question

ce Final Exam haileygray Project2 - Goog COP Project 2 pdf - Googl 3449/quizzes/1547338/take 28 ? \( \frac{1}{7} \ln \left(1+7 y^{4}\right)-\frac{1}{4 e^{x^{4}}}=C \) Question 3 0.5 pts Find the general solution \( y(t) \) to the given differential equation \[ 2 y^{\prime \prime}-2 y^{\prime}+25 y=0 . \] ? \( y(t)=c_{1} e^{t} \cos (7 t)+c_{2} e^{t} \sin (7 t) \) ? \( y(t)=c_{1} e^{\sqrt{7} t / 2}+c_{2} e^{-\sqrt{7} t / 2} \) ? \( y(t)=c_{1} e^{t / 2} \cos (\sqrt{7} t)+c_{2} e^{t / 2} \sin (\sqrt{7} t) \) ? \( y(t)=c_{1} e^{7 t / 2}+c_{2} e^{-7 t / 2} \) ? \( y(t)=c_{1} e^{t / 2} \cos (7 t / 2)+c_{2} e^{t / 2} \sin (7 t / 2) \) Question 4 0.5 pts Find the general solution \( y(t) \) to the given initial value problem.

          ce Final Exam
haileygray Project2 - Goog
COP Project 2 pdf - Googl
3449/quizzes/1547338/take

28
? \( \frac{1}{7} \ln \left(1+7 y^{4}\right)-\frac{1}{4 e^{x^{4}}}=C \)

Question 3

0.5 pts

Find the general solution \( y(t) \) to the given differential equation
\[
2 y^{\prime \prime}-2 y^{\prime}+25 y=0 .
\]
? \( y(t)=c_{1} e^{t} \cos (7 t)+c_{2} e^{t} \sin (7 t) \)
? \( y(t)=c_{1} e^{\sqrt{7} t / 2}+c_{2} e^{-\sqrt{7} t / 2} \)
? \( y(t)=c_{1} e^{t / 2} \cos (\sqrt{7} t)+c_{2} e^{t / 2} \sin (\sqrt{7} t) \)
? \( y(t)=c_{1} e^{7 t / 2}+c_{2} e^{-7 t / 2} \)
? \( y(t)=c_{1} e^{t / 2} \cos (7 t / 2)+c_{2} e^{t / 2} \sin (7 t / 2) \)

Question 4

0.5 pts

Find the general solution \( y(t) \) to the given initial value problem.

ce Final Exam
haileygray Project2 - Goog
COP Project 2 pdf - Googl
3449/quizzes/1547338/take

28
? (1)/(7)ln(1+7 y^4)-(1)/(4 e^x^4)=C

Question 3

0.5 pts

Find the general solution y(t) to the given differential equation

2 y^''-2 y^'+25 y=0 .

? y(t)=c1 e^tcos (7 t)+c2 e^tsin (7 t)
? y(t)=c1 e^√(7) t / 2+c2 e^-√(7) t / 2
? y(t)=c1 e^t / 2cos (√(7) t)+c2 e^t / 2sin (√(7) t)
? y(t)=c1 e^7 t / 2+c2 e^-7 t / 2
? y(t)=c1 e^t / 2cos (7 t / 2)+c2 e^t / 2sin (7 t / 2)

Question 4

0.5 pts

Find the general solution y(t) to the given initial value problem.

Added by Aaron M.

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