ch babies first crawl. [ egin{array}{|c|c|c|c|c|c|c|} hline 49 & 31 & 46 & 34 & 39 & 27 \ hline 49 & 39 & 54 & 26 & 37 & 28 \ hline end{array} ] Chi-Square Distribution Critical Values Table Click the icon to view the table of critical values of the chi-square distribution Select the correct choice below and fill in the answer boxes to complete your choice Use ascending order. Round to three decimal places as needed. A. If repeated samples are taken, 99% of them will have the sample standard deviation between ◻ and B. There is a 99% probability that the true population standard deviation is between ◻ and C. There is 99% confidence that the population standard deviation is between ◻ and Question 22 of 24 ch babies first crawl 34 27 31 46 49 26 37 28 49 39 54 Click the icon to view the table of critical values of the chi-square distribution Chi-Square Distribution Critical Values Table 4 Chi-Square Distribution Area to the Right of Critical Value 0.125 0.605 0.010 0.95 Degrees of Freedom 6 9 7 5 9 5 0.50 0.995 0.99 6 6 3 5 9 9 7 5 9 5
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- First, calculate the mean of the data: Mean = (49 + 31 + 46 + 34 + 39 + 27 + 49 + 39 + 54 + 26 + 37 + 28) / 12 Mean = 39 - Next, calculate the squared differences from the mean for each data point: (49-39)^2, (31-39)^2, (46-39)^2, (34-39)^2, (39-39)^2, Show more…
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Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) below. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 1.3 0.9032 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 0.9147 0.9162 1.4 0.9192 0.9207 0.9222 0.9236 0.9251 0.9265 0.9279 0.9292 0.9306 1.5 0.9332 0.9345 0.9357 0.937 0.9382 0.9394 0.9406 0.9418 0.9429 1.6 0.9452 0.9463 0.9474 0.9484 0.9495 0.9505 0.9515 0.9525 0.9535 1.7 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.9608 0.9616 0.9625 1.8 0.9641 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 0.9699 a. If the probability that Z is between negative 1.59 and 1.88 is 0.914. b. If the probability that Z is less than negative 1.59 or greater than 1.88 is 0.086. c. What is the value of Z if only 4.5% of all possible Z values are larger?
Tim T.
Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) below. a. If the probability that Z is between negative 1.59 and 1.88 is 0.914 b. If the the probability that Z is less than negative 1.59 or greater than 1.88 is 0.086 c. If the the value of Z if only 4.5% of all possible Z values are larger is 1.70 d. Between what two values of Z (symmetrically distributed around the mean) will 91.08% of all possible Z values be contained?
Three different distributions There are 559 full-service restaurants in Delaware. The mean number of seats per restaurant is 99.2. [Source: Data based on the 2002 Economic Census from U.S. Census Bureau.] Suppose that the true population mean μ = 99.2 and standard deviation σ = 21 are unknown to the Delaware tourism board. They select a simple random sample of 50 full-service restaurants located within the state to estimate μ. The mean number of seats per restaurant in the sample is M = 103.4, with a sample standard deviation of s = 18.2. The standard deviation of the distribution of sample means (that is, the standard error, σM) is ______ . (Note: Although μ and σ are unknown to the Delaware tourism board, they are known to you for the purposes of calculating these answers.) The standard or typical average difference between the mean number of seats in the 559 full-service restaurants in Delaware (μ = 99.2) and one randomly selected full-service restaurant in Delaware is ______ . The standard or typical average difference between the mean number of seats in the sample of 50 restaurants (M = 103.4) and one randomly selected restaurant in that sample is ______ . The standard or typical average difference between the mean number of seats in the 559 full-service restaurants in Delaware (μ = 99.2) and the sample mean of any sample of size 50 is ______ . The z-score that locates the mean number of seats in the Delaware tourism board's sample (M = 103.4) in the distribution of sample means is ______ . Use the unit normal tables and accompanying figures to answer the question that follows. To use the tables, click on the Unit Normal Tables tab below the figures, and use the dropdown box to select the desired range of z-score values. A table of the proportions of the normal distribution corresponding to that range of z-scores will appear. If you need a different range of z-scores, simply click on the box again and select a new range. Suggestion: Make a sketch of the area under the normal distribution you are seeking. This sketch will help you determine which column(s) of the normal table to use in determining the appropriate probability.
Ameer S.
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