00:01
Side of the square forming steel rod is a equal to 3 .48 cross 10 raised to minus 2 meter.
00:16
Temperature of one end of the rod t1 is equal to 78 .2 degrees celsius.
00:25
2 is equal to 17 .5 degrees celsius.
00:32
L.
00:34
L is equal to 0 .5 meter.
00:39
Now from the given figure, the area of cross -section of the stainless steel is given by as equal to a square, which is equal to 3 .48 cross 10 raise to minus 2.
00:57
Whole square.
00:59
So as is equal to 1 .21 cross 10 raise to minus 3 meter square.
01:08
From the given cross section of the rod we can write diagonal of the square d is equal to square root of a square plus a square is equal to on simplifying a times square root of 2.
01:27
The area of cross section of the circular rod is represented by a total which is equal to pi by 4 t square equal to pi by 4 times d is a times square root of 2 whole square on simplifying we get area total equal to 1 .9 cross 10 raised to minus 3 meter square the cross sectional area of the iron rod is a .i.
02:07
Equal to 0 .69 cross 10 raise to minus 3 meter square.
02:13
The rate of heat conducted through the stainless steel can be calculated as dq by dt of steel of steel equal to ks times as multiplied by t1 minus t2 by length...