00:01
Okay, so i see that you need help with this question.
00:02
It says, annual starting salaries for college graduates with degrees in business administration are generally expected to be between 30 and $50 ,000.
00:11
Assuming 95 % confidence interval estimate for the population means starting salaries desired.
00:17
What is the planning value for the population standard deviation? okay, so you already got that's 5 ,000.
00:24
How large of a sample should be taken if the desired margin of error is 300? so 300 equals 1 .96 times 5 ,000 divided by the square root of n.
00:43
So 300 divided by 1 .96.
00:48
And so that's 153 .06 equals 5 ,000 divided by the square root of n.
00:58
So then it's the square root of n equals 5 ,000 divided by 153 .06.
01:05
And so that's 32 .666.
01:10
And then i'm going to square both sides to get rid of the square root.
01:14
So n equals 1 ,067 .128.
01:21
So that's 1 ,060, i'm sorry, 1 ,068.
01:28
And then $270.
01:31
So then that would be 270 equals 1 .96 times 5 ,000 divided by the square root of n.
01:41
So 270 divided by 1 .96...