Question

A charge q1=10mu C is at position (x1,y1), another charge q2=5mu C is at position (x2,y2) and a third charge q3=8mu C is at position (x3,y3). Find the x component of the total force exerted by q1 and q2 on q3. The unit of your answer is N. ($k = frac{1}{(4pi epsilon_0)} = 8.99 imes 10^9 Nm^2/C^2$) Assume x1=7cm, y1=5cm x2=3cm, y2=7cm x3=7cm,y3=10cm

          A charge q1=10mu C is at position (x1,y1), another charge q2=5mu C is at position (x2,y2) and a third charge q3=8mu C is at position (x3,y3). Find the x component of the total force exerted by q1 and q2 on q3. The unit of your answer is N. ($k = frac{1}{(4pi epsilon_0)} = 8.99 	imes 10^9 Nm^2/C^2$)

Assume
x1=7cm, y1=5cm
x2=3cm, y2=7cm
x3=7cm,y3=10cm

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$A charge q1=10mu C is at position (x1,y1), another charge q2=5mu C is at position (x2,y2) and a third charge q3=8mu C is at position (x3,y3). Find the x component of the total force exerted by q1 and q2 on q3. The unit of your answer is N. (k = frac1(4pi epsilon0) = 8.99 imes 10^9 Nm^2/C^2) Assume x1=7cm, y1=5cm x2=3cm, y2=7cm x3=7cm,y3=10cm$

Added by Ricardo A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

09/21/2023

Step 1

We can use the distance formula: d = sqrt((x2-x1)^2 + (y2-y1)^2) For q1 and q3: d1 = sqrt((7-7)^2 + (10-5)^2) = 5 cm For q2 and q3: d2 = sqrt((3-7)^2 + (7-10)^2) = 5 cm Show more…

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Charge q1 = -10uC is at position (x1, Y1). Another charge q2 = -5uC is at position (x2, y2) and the third charge q3 = -81uC is at position (x3, y3). Find the x component of the total force exerted by q1 and q2 on q3. The unit of your answer is N. (k = 8.99x10^9 Nm^2/C^2) (

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