A charge of -5.62 µC is traveling at a speed of 7.50 × 10$^6$ m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 59.0°. A force of magnitude 6.37 × 10$^{-3}$ N acts on the charge. What is the magnitude of the magnetic field?
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The formula for the magnetic force on a moving charge is given by: F = q * v * B * sin(theta) where: F is the magnetic force q is the charge v is the velocity of the charge B is the magnetic field strength theta is the angle between the velocity and the magnetic Show more…
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