00:01
To the reaction that i've written here, the, the, um, the voltage cell constructed from the two half cells i've referenced right here.
00:14
And i wrote that i like to start with my cathode.
00:18
The cathode, um, is the, is the electrode at which reduction occurs.
00:28
So it's going to be the higher standard reduction potential.
00:33
So it'll be this, this, substance.
00:38
And that'll be written as f .e3 plus plus 1e minus, and that is going to give us fe2 plus.
00:54
And that was what needs to be entered into the equation for the cathode.
00:59
The anode will be the other reaction, which will be this one, and we're going to write al yields, al3 plus aq, plus plus 1, excuse me, 3e minus.
01:27
And when we are preparing our spontaneous cell reaction, we'll have to take this times 3.
01:38
So i will get als plus 3, i did that wrong, no, i did that right, plus 3fe, 3 plus, and here i will have al, 3 plus, and here i will have al, 3 plus aq plus fe2 ,3, f .e2 plus.
02:18
It gives me 6, 7, 8, 9, and 9.
02:21
Okay...