00:01
In this problem, we're given spectroscopy data for a structure with the formula s.
00:06
S.
00:06
8, h8 ,02.
00:09
And our first appears finding what we call degrees of unsaturation.
00:13
This will tell us how many pie bonds and rings we have.
00:16
So we multiply the number of carbons by 2 and add 2, subtract the number of hydrogens, divide by 2.
00:23
Now, this gives us 5.
00:25
Typically, when you see 5, you should be looking for evidence of a benzene ring, and then some other functional groups.
00:32
So either an alkene or something with a carbonyl.
00:37
Now, if we look at your ir data, you'll notice around 1 ,700 inverse centimeters.
00:44
You have this nice kind of curved peak.
00:47
This is evidence of a carbonyl.
00:50
And the other key evidence, notice at 2 ,700 and 2 ,800, you have two peaks.
00:58
This is evidence of an aldehyde.
01:02
So now when we look at your proton nmr data, you'll notice that you have one hydrogen that's out near 10.
01:13
That's going to be your aldehyde...