00:01
So, here we have been given with the reaction ca3p2 solid plus 6h2o liquid forming here 3caoh whole twice solid plus 2 ph3 gas.
00:14
So, firstly we have to tell the maximum amount of phosphine that is ph3 which can be formed formed from 921 .7 g of ca3p2 and 5 mol of h2o.
00:39
So here if we see then 1 mol ca3p2 reacts with 6 mol water which means here 182 .19 g gram ca3p2 because 182 .19 gram is the molar mass of ca3p2 would react with 6 multiplied by 18 gram of h2o since 18 gram is the molar mass of water which means 182 .19 gram ca3p2 would react with 108 gram of h2o.
01:17
So here 921 .7 gram ca3p2 would react with 546 .37 gram of h2o.
01:29
But here we have 5 mole of h2o which means 5 multiplied by 18 gram of h2o that that is 90 gram of h2o.
01:38
Since here the amount of water is less than the required.
01:42
So here water would be the limiting reagent.
01:48
So the product amount would be decided by water.
01:51
So corresponding to this from the balanced equation, we can see that 6 mole of water that is h2o here produces 2 moles of phosphine gas that is ph 3.
02:04
So, here we have 5 moles of water...