00:01
Hello students, in this question there are four part.
00:03
In the first part we have to find out the oxidation state of the given atom or element or the ion.
00:09
So here the chlorine is a neutral molecule and the oxidation state of the chlorine atom here is equal to zero.
00:18
Here the oxidation state of the sodium atom will be equal to one.
00:22
Here the oxidation state of potassium is equal to plus one and the fluorine is equal to minus one which is obtained by crisscrossing the values and here the oxidation state of the sulfur is plus six and the oxygen is minus two.
00:39
Here the oxidation state of potassium is plus two and the oxygen is minus two.
00:45
Here the chromium is in its neutral state.
00:47
Therefore, the oxidation state of chromium is equal to zero.
00:51
Here the chromium exists in the plus three oxidation state.
00:54
Therefore, the oxidation state is plus three.
00:56
Here ccl4, the oxidation state of carbon is plus four and the chlorine is minus one.
01:03
Here the strontium bromide, the oxidation state of the strontium is plus two and bromine is minus one which is obtained by crisscrossing the value.
01:13
Here so3, the oxidation state of sulfur is plus six and the oxygen is minus two and in no3, the oxidation state of nitrogen is plus seven and the oxygen is minus two.
01:29
So these are the values of the various oxidation state of the elements and the ions and in the upcoming part we have to determine whether the reaction is a redox reaction and we have to find out which substances oxidized and reduced.
01:42
So first of all going with the equation, the oxidation state of magnesium here is zero and hydrogen is plus one and oxygen is minus two.
01:51
Here the oxidation state of magnesium is plus two and the hydrogen is zero and oxygen is minus two.
01:57
So here the oxidation state of magnesium increases from zero to plus two.
02:02
Therefore, the magnesium is oxidized over here and the oxidation state of the hydrogen is reduced from plus one to zero.
02:11
Therefore, the reduced substance here is the hydrogen.
02:14
And coming to the second equation, now we have to determine the oxidation state of each of the elements present over here.
02:22
The oxidation state of hg2 is plus two, the nitrogen is plus five, oxygen is minus two, the potassium is plus one, bromine is minus one and here hg is plus two, bromine is minus one and potassium is plus one, nitrogen is plus five and oxygen is minus two and the oxidation state of all the elements and the atoms remain same over here.
02:45
Therefore, it is not a redox reaction...