00:01
Hello everyone, let's start the question.
00:03
In this question, the information given to us is that we have 0 .9 percentage weight by volume of nacl, that is sodium chloride solution, for which we are provided with the value of osmotic pressure, that is, pi as 3 .91atm at a temperature of 25 degrees celsius.
00:23
We are also provided with a molar mass of sodium chloride as 58 .44 gram per mole.
00:32
In the first part of the question, we are asked to calculate the molarity in this case.
00:37
So if we go as per the information which is given, 0 .9 percentage w by v of sodium chloride solution implies that 0 .9 grams of nacl, that a sodium chloride, is actually present in 100 milliliters of the solution.
01:05
So now we can easily calculate its molarity.
01:09
As we know that molarity is equal to the number of moors of solute divided by the volume of solution in liters.
01:23
Number of modes of solute which in this case is sodium chloride...