00:01
First of all, let's have a look what all is given in the problem.
00:05
Given is a table is given and what we are supposed to find out is we need to complete the given table.
00:14
We need to complete the given table.
00:19
So first thing is that let's draw the given table.
00:25
Let's draw the given table first.
00:27
First one that is given is aluminium.
00:32
Next one is fluorine.
00:37
Sodium followed by strontium and the last one is oxygen.
00:43
Now what we have to find is we need to tell whether these will gain electron or lose electron and the ions that will be formed.
00:53
So we know that aluminium, its electronic configuration is what? if we look at the aluminum, we know that it belongs to 13th group, that is boron family.
01:04
So it has three valence electrons.
01:06
So it will lose three electrons to form al plus three ion that is ketion.
01:16
Now similarly for fluorine we know that it belongs to the halogens.
01:21
So it's outermost shell contain group number is 17.
01:24
Outermose shell contains seven valence electron.
01:28
That means it will accept one electron...