Chloroform, CHCl3, is formed from methane and chlorine in the following reaction:
CH4(g) + 3 Cl2(g) → 3 HCl(g) + CHCl3(g)
Calculate ΔrH°, the enthalpy change for this reaction, using the enthalpies of formation of CO2(g), H2O(ℓ), CHCl3(g) (ΔfH° = -103.1 kJ/mol), and the enthalpy changes for the following reactions:
CH4(g) + 2 O2(g) → 2 H2O(ℓ) + CO2(g)
ΔrH° = -890.4 kJ/mol-rxn
2 HCl(g) → H2(g) + Cl2(g)
ΔrH° = +184.6 kJ/mol-rxn