Question

Choose the equation that best describes the net torque about point P (a point on the end of the beam) on the 1.5m long uniform beam shown in the figure. Point C indicates the location of the center of mass. 58 N 73° 26° P 71 N 45° 48 N Sign convention: CCW = positive. (A positive net torque would cause a counter-clockwise (CCW) rotational acceleration). [Reminder: The magnitude of a torque due to a force F about a pivot point is determined by $| au| = |r imes F| = rFsin heta.]$ $ au_{net} = (1.5)(58)sin(73^{circ}) - (0.75)(71)sin(45^{circ}) - (1.5)(48)sin(26^{circ})$ $ au_{net} = (1.5)(58)sin(73^{circ}) - (0.75)(71)sin(45^{circ})$ $ au_{net} = (1.5)(58)sin(73^{circ}) - (0.75)(71)sin(45^{circ}) - (0.75)(48)sin(26^{circ})$

          Choose the equation that best describes the net torque about point P (a point on the end of the beam) on the 1.5m long uniform beam shown in the figure. Point C indicates the location of the center of mass.
58 N
73°
26°
P
71 N
45°
48 N
Sign convention: CCW = positive. (A positive net torque would cause a counter-clockwise (CCW) rotational acceleration).
[Reminder: The magnitude of a torque due to a force F about a pivot point is determined by $|	au| = |r 	imes F| = rFsin	heta.]$
$	au_{net} = (1.5)(58)sin(73^{circ}) - (0.75)(71)sin(45^{circ}) - (1.5)(48)sin(26^{circ})$
$	au_{net} = (1.5)(58)sin(73^{circ}) - (0.75)(71)sin(45^{circ})$
$	au_{net} = (1.5)(58)sin(73^{circ}) - (0.75)(71)sin(45^{circ}) - (0.75)(48)sin(26^{circ})$

Choose the equation that best describes the net torque about point P (a point on the end of the beam) on the 1.5m long uniform beam shown in the figure. Point C indicates the location of the center of mass.
58 N
73°
26°
P
71 N
45°
48 N
Sign convention: CCW = positive. (A positive net torque would cause a counter-clockwise (CCW) rotational acceleration).
[Reminder: The magnitude of a torque due to a force F about a pivot point is determined by | au| = |r imes F| = rFsin heta.]
aunet = (1.5)(58)sin(73^circ) - (0.75)(71)sin(45^circ) - (1.5)(48)sin(26^circ)
aunet = (1.5)(58)sin(73^circ) - (0.75)(71)sin(45^circ)
aunet = (1.5)(58)sin(73^circ) - (0.75)(71)sin(45^circ) - (0.75)(48)sin(26^circ)

Added by William G.

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