00:01
Okay, so here we wanted to select the tree statement regarding the structure of no2 minus in its resonance forms.
00:05
So if we think about the nitrite resonance or the nitrite loose structure, we can go ahead and actually draw it first.
00:12
So nitrogen has five valence electrons and oxygen has six, but we have two oxygens.
00:18
So overall, this is going to be 17 electrons.
00:22
We also have a negative charge, which gives us one more electron to work with.
00:26
So overall, there's going to be 18 electrons in our resonance.
00:30
In our loo structure.
00:32
So first we'll start off by putting nitrogen in the middle because it's at least electronegative and orienting the oxygens around it.
00:38
And then what we want to do is fill the octet of the oxygens.
00:42
So by putting the two bonds in, we've used up four electrons.
00:47
And then by filling the octet of the oxygens, we use up 12, leaving us with two.
00:53
Now whenever you have electrons left over after satisfying the octet of the outside, then you put them on the central atom.
01:08
So this leaves us using all of our valence electrons, but the octet of nitrogen still isn't quite satisfied.
01:16
So what we can do is we can calculate formal charge to see where we can put the double bonds...