Question

Cindy recorded the number of customers who visited her new shop during the week: Day Customers Wednesday 18 Thursday 20 Friday 25 Saturday 17 She expected to have 20 customers each day. To determine whether the number of customers follows a uniform distribution, a chi-square test for goodness of fit should be performed (alpha = 0.10). chi squared equals sum from blank to blank of fraction numerator left parenthesis O minus E right parenthesis squared over denominator E end fraction Using the data above, what is the chi-square test statistic? a.) 0.55 b.) 3.51 c.) 1.9 d.) 0.37

          Cindy recorded the number of customers who visited her new shop during the week:

Day	Customers
Wednesday	18
Thursday	20
Friday	25
Saturday	17

She expected to have 20 customers each day. To determine whether the number of customers follows a uniform distribution, a chi-square test for goodness of fit should be performed (alpha = 0.10).

chi squared equals sum from blank to blank of fraction numerator left parenthesis O minus E right parenthesis squared over denominator E end fraction

Using the data above, what is the chi-square test statistic?


a.)
0.55

b.)
3.51

c.)
1.9

d.)
0.37

Added by Raquel L.

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