In the circuit of the figure ? = 2.40 kV, C = 7.80 ?F, R1 =...

In the circuit of the figure ? = 2.40 kV, C = 7.80 ?F, R1 = R2 = R3 = 0.890 M?. With C completely uncharged, switch S is suddenly closed (at t = 0). At t = 0, what are (a) current i1 in resistor 1, (b) current i2 in resistor 2, and (c) current i3 in resistor 3? At t = ? (that is, after many time constants), what are (d) i1, (e) i2, and (f) i3? What is the potential difference V2 across resistor 2 at (g) t = 0 and (h) t = ??

Transcript

00:01 Given, voltage is 2 .4 kilowolts and that capacitance is 7 .8 micro -ferret and that resistance r1 is equal to r2 is equal to r3 which is 0 .890 mega -oom and the figure as shown.

00:23 Now at t is equal to 0, capacitor behave as short.

00:31 Circuit.

00:33 So that comes out to be current will be v by r1 and that r2 and r3 in parallel.

00:39 So that r2 r3 upon r2 plus r3 and then putting values which is 2 .4 into 10 raised to power 3 divided by 0 .890 plus 0 .890 into 0 .890 divided by 2 .890 divided by 2 .890 divided by 2 .890 into 0 .890 and then multiply by into 10 raised to power 6 right for mega so that will be current comes out to be 2 4 00 divided by 1 .335 into 10 to power 6 and that comes out to be i is equal to 1 .797 7 into 10 raised to power minus 3 ampere and that is the calculated value.

01:36 Now talking about current in resistance r2 that will be is equals to i by 2 because same is getting divided into both travels right? so that will be 1 .797 divided by 2 into 10 raised to power minus 3 which is equal to to 8 .988 into 10 raised to power minus 4 ampere and that is the correct answer.

02:07 And now for resistance r3 which is also equal to i2, so that is also 8 .988 into 10 raised to power minus 4 ampere and that is the correct answer.

02:20 Then current will be i1 is equal to v v divided by r1 plus r2.

02:27 So putting values 2 ,400 divided by 0 .890 into 10 raised to power 6.

02:35 So that comes out to be 2 .696 into 10 ways to power minus 3 ampere.

02:42 And that is the correct answer...

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