00:01
So to solve this problem, we have been given various values.
00:08
Probability of s1 is 0 .2.
00:14
Probability of s2 equal to 0 .5.
00:20
Probability of s3 equal to 0 .3.
00:35
Probability of a given s1 equal to 0 .2.
00:45
Probability of a given s2 equal to 0 .1 probability of a given s 3 equal to 0 .3 so first we need to find part a probability of s1 given a the formula is p a given s 1 multiply probability of s 1 divide by p a given a given s 1 multiply ps 1 p .a s 2 multiply p .a s 2 multiply p s 2 p a given s 3 multiply ps 3 so we substitute the values in the formula p a s 1 is 0 .2 multiply ps 1 that is also 0 .2 divided by p .s 1 is 0 .2, multiply 0 .2 plus p .s2 is 0 .1, multiply 0 .5 plus p .s3 is 0 .3, multiply ps3, that is 0 .3.
03:05
So when we calculate it, we get 0 .04 divided by 0 .18.
03:20
So the answer is 0 .04.
03:23
0 .2 to 2 to 2, up to 4 digits.
03:29
So this is the answer of p s1 given a...