00:01
Students welcome back here we have to find out the magnetic nature of a and b okay so the compound a is given to be k2 and i cn 4 okay and the compound b is given to be k2 n i c l4 okay so first of all that uh this compound a cn is a strong legion okay so this compound a will be an inner it will be an inner complex and b will be an outer complex because cl is a weak field ligand okay so now if i just draw if i just calculate the number of electrons in n i 2 plus here the state of n i is n i 2 plus so there are total 3d 8 okay so there are total 8 electrons and nickel 2 plus okay so if i try drawing this 3d orbital, it would be something like this where there will be 5 orbitals, right, and there will be 8 electrons in this manner.
01:09
Right, so 2 electrons will be unpaired.
01:12
Now, i have to, first of all, i have to draw this structure a.
01:18
So, is cn4 is a strong philigant, okay? so what it will do, it will shift this electron here, and then it will, will, cn will insert its electron in the orbitals, okay, in the d orbital and then the s orbitals.
01:36
So it will form up diamagnetic compound, diamagnetic compound, okay, because no electron is unpaired...