Question

A point charge q1 = -5.5 ?? is placed at x = 0 and y = +5 cm. A second point charge q2 = -3 ?? is placed at x = +5 cm and y = 0. Determine the magnitude of the net electric field at the origin and the direction of the electric field as an angle measured from the +x axis. Use k = 9.00 × 10^9 N·m^2/C^2. Magnitude = 18532134.25 N/C Direction = 60.95 ° from +x axis

          A point charge q1 = -5.5 ?? is placed at x = 0 and y = +5 cm. A second point charge q2 = -3 ?? is placed at x = +5 cm and y = 0. Determine the magnitude of the net electric field at the origin and the direction of the electric field as an angle measured from the +x axis. Use k = 9.00 × 10^9 N·m^2/C^2.

Magnitude = 18532134.25 N/C
Direction = 60.95 ° from +x axis

A point charge q1 = -5.5 ?? is placed at x = 0 and y = +5 cm. A second point charge q2 = -3 ?? is placed at x = +5 cm and y = 0. Determine the magnitude of the net electric field at the origin and the direction of the electric field as an angle measured from the +x axis. Use k = 9.00 × 10^9 N·m^2/C^2.

Magnitude = 18532134.25 N/C
Direction = 60.95 ° from +x axis

Added by Tommy S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

10/02/2023

Step 1

For charge q1: q1 = -5.5 µC = -5.5 x 10^{-6} C r1 = 5 cm = 0.05 m k = 9.00 x 10^9 N m^2/C^2 The electric field due to q1 at the origin is given by: E1 = k * |q1| / r1^2 E1 = (9.00 x 10^9 N m^2/C^2) * (5.5 x 10^{-6} C) / (0.05 m)^2 E1 = 19800000 N/C For charge Show more…

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A point charge q1 = -5.5 µC is placed at x = 0 and y = +5 cm. A second point charge q2 = -3 µC is placed at x = +5 cm and y = 0. Determine the magnitude of the net electric field at the origin and the direction of the electric field as an angle measured from the +x axis. Use k = 9.00 x 10^9 N·m^2/C^2. Magnitude: 1.853213425 x 10^5 N/C Direction: 60.95° from +x axis