A student performing this lab experiment receives his...

A student performing this lab experiment receives his unknown solution, may contain ( SO4 2-, PO4 3-, Cl-, and NO3- ), and begins to conduct the following tests to identify the anions present 1) When the unknown solution was treated with Ba(NO3)2 and few drops of 5 M aqueous NH3, a white precipitate formed. 2) The white precipitate from 1 dissolves partially when few drops of 6 M HCl is added. Then no precipitate was formed when ammonium molybdate was added to the solution. 3) The resulting solution from step 1 was acidified with 6M HCl before the addition of aqueous silver nitrate which forms a white precipitate. 4) Another unknown solution was acidified with 6M H2SO4. No observation occurred after the addition of excess FeSO4 solution and conc. H2SO4. Which anions were present in the student's unknown solution? Select one or more: SO4 2- PO4 3- Cl- NO3-

Transcript

00:01 So here in the question, first of all, we are going to be solving the first part, where we are going to do the kind of explanation, which is basically based on we need to find out the unknown solutions and which of the ppd is going to be forming.

00:15 So i can write it over here that unknown solution when we are going to mix up or going to react with b .a.

00:25 N .3, 2, plus n .h4, o h, h, it's going to be forming baso4 in the form of what white ppity is going to be forming up over here or else i can say that unknown solutions which is containing the sulphate iron over here we are going to see the sulphate iron when we are going to be treated with a barym nitrate it is always going to give us a white ppting so that is a kind of a solution i can say for the first part moving ahead with the second part i would like to write it that this white ppt i can write it over here that is in the form of b a s o4 is a partially we can say soluble where it is going to be soluble in the acid basically we are going to be taken as an acidic medium i would like to write it in the acidic medium so i can write it that reaction is going to be formed baso4 that is a white ppt white precipitate plus ammonium amonium mollibate where it will be having a no ppity is going to be form up over here with a white precipitations of a baryum sulfate when we are going to be added with an ammonium mollablate then no precipitation is going to be formed why it is going to sew because the absence of the phosphate iron group is not been present so it's not going to be form up so this is an solution for the part two moving ahead with the third part i can write it so resulting what will be the solutions is going to be come up from the first step we are going to be using up that that will be the c l ian cl minus and we are going to be using from the first step along with that 6m of molar of hcl we are going to adding more agn .o3 we are going to get it that is in the aquas form we are going to get it here as an agcl precipitate as in which precipitate we are going to get it over here as in white ppt so in the resulting solutions is going to be get from the first part that is the presence of a chloride so chloride ion is going to be reacted with what a gno3 and will give the precipitate in the form of a white ppd of agcl so this is our solution part for the third part moving ahead i can write it fourth part so here we are going to be using our unknown solution so unknown solution is going to be represent as an no3 we are going to taking fourth part unknown solution that will be the no3 no 3 no minus 3 plus 6 molar of edge to s .4 plus feso 4 plus concentrated h2so4.

03:45 So here i would like to get it no such kind of observation we are going to be found out over here.

03:52 So there will be a no product is going to be formed or no observation...

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