CO (g) + 2H2 (g) → CH3OH (l) ΔHrxn = -128 kJ Calculate the C—H bond energy given the following bond enthalpies: D(C≡O) = 1072 kJ, D(H-H) = 436 kJ, D(C-O) = 358 kJ, D(O-H) = 463 kJ
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Step 1
This is given by the sum of the bond enthalpies of the reactants: Energy to break CO bond = D(C≡O) = 1072 kJ Energy to break 2 H2 bonds = 2 * D(H-H) = 2 * 436 kJ = 872 kJ Total energy to break bonds in reactants = 1072 kJ + 872 kJ = 1944 kJ Show more…
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