00:01
Hello students, let us have a look on this question.
00:02
So, in this question we have given three appliances, one is the coffee maker, second is the toaster and third is the waffle maker and all are connected in series with 120 volt battery and we have to find the current in each appliances when operating independently.
00:17
Now, we have given here that we know first formula is what for first question, v is equal to power is equal to v into i.
00:25
So, we have to find the current in each, so i can say current is equal to i is equal to simply p by v.
00:31
Now, i am just finding first one for the coffee maker, for the coffee maker i am finding the current.
00:37
So, formula is p by v, so p is we have given in the question 1180 divided by voltage is equal to 120.
00:43
So, finally, we will get the current is equal to 9 .83 ampere.
00:47
Moving on the toaster, so we have given the power is 1000 divided by 120 again, so we will get again this 8 .33 ampere.
00:56
Moving on the current of waffle maker, so this is the power of 1380 divided by 120.
01:04
So, finally, we will have the power current of 1 .5 ampere.
01:08
This is the question number 1.
01:10
Now, we have to find total current if all are in connected in parallel.
01:15
So, for that we have to find the resistance first and we know p is equal to i square r.
01:21
So, from this formula i can find the r is equal to p by i square because i now i have power in the question given and current i just found here.
01:31
So, resistance for the coffee maker is equal to simply 1180 by i square is what 9 .83 whole square.
01:39
After solving this i will get the resistance is 12 .21 ohm.
01:43
Now, moving on the toaster, so this is equal to 1000 divided by 8 .33 whole square.
01:51
So, finally, we will have 14 .4 ohm.
01:55
Then for last one is resistance of waffle maker...