College Physics II, 2024 Summer 1. Four charges are arranged...

College Physics II, 2024 Summer 1. Four charges are arranged at the corners of a square 3 m on a side as shown in the diagram. A) Calculate the magnitude and direction of the Coulomb force on a charge of 1.0x10^-4 C located at point P. B) If the charge of Q2 becomes negative, what will be the new results force?

Transcript

00:01 Hi, here in this given problem this is a square shaped structure having three charges at its three vertices.

00:16 Starting from this q1, which is a positive charge, having magnitude of 1 into 10th of minus 4 kulum.

00:27 Then this is q2.

00:29 At the bottom right corner, this is also positive.

00:34 And this is 2 into 10 to 1 to learn.

00:39 Third chart, this is also positive at point.

00:42 At the third point, this is q3.

00:45 And that is having a magnitude of 3 into 10 to par minus 4.

00:51 This is the point p, observation point at which we put a charge q, such that this q is, that is also 1 into 10 to 1 .10, the bar minus vol boulon side of the square is three meter each so the diagonal length of the diagonal that will be side root 2 means 3 into root 2 meter now the forces acting at this observation point q as positive will be repelled by the positive so this is the force acting at q small q due to q 3 it is given as f3 then due to this q1 that is also repulsive force f due to 1 then due to 2 due to q2 diagonally outward f due to 2 okay and this angle will be 45 degrees so using coul arm's law f1 will be given by k into q1 into q by a square plugging in the known values for k this is 9 1 to 10 per 9 q1 1 into 10 which is the power minus 4 small q that is also 1 into 10 to the power minus 4 divided by square of side that is 9 will be cancelled so leaving behind this is 10 newton for f1 going up then f2 k into q 2 2 into q divided by diagonal this is the diagonal of this square and obviously this diagonal will come out to be able to 3 root 2 meter and having a square of it plugging in other known values for k again this is 9 into 10 to power 9 q2 is 2 into 10 to power minus 4 small q again 1 into 10 to par minus 4 divided by a square of 3 root 2 means that is 9 multiplied by 2 can canceling 9, canceling 2, ultimately it also comes out to be equal to 10 newton.

03:18 F2 also.

03:19 Finally, f3.

03:23 For k again, 9 into 10 dash to par 9, q3, q3, that is 3 into 10 raised to the par minus 4, and small q again 1 into 10 to the power minus 4.

03:41 Divided by square of 3 again means 9, it will be cancelled here.

03:45 So it comes out to be equal to 13 newton.

03:49 Okay...

Question

Please give Ace some feedback