00:01
Hi everyone so in this question they ask combustion analysis of tolune a common organic solvent gives 5 .86 milligrams of co2 and 1 .37 milligram of h2 if the compound contains only carbon and hydrogen hydrogen what is its empirical formula so given wco2 that is equal to 5 .86 milligram and that is equal to 0 .00586 gram.
00:51
Then weight of water that is equal to 1 .37 milligram that is equal to 0 .00137 gram empirical formula you have to calculate then weight of carbon that is equal to 12 upon 44 into 0 .00586 that is equal to 0 .00186 that is equal to 0 .001598 then second, weight of hydration, that is equal to 2 divided by 18 into 0 .037, that is equal to 0 .00137.
02:35
Now finding empirical formula.
02:45
Now for finding out empirical formula, first you have tried element, the next weight, next n, next, simplest n, simplest n, next whole number.
03:19
So first element is carbon, second one is hydrogen.
03:25
So weight is 0 .001598.
03:34
Hydrogen weight is 0 .30 -2 -2 -2.
03:45
So, yon is 1 .3316 into 10 -2 minus 4...