00:01
Okay, so to solve for this, let's write first the balance equation.
00:04
First question is, what is the balanced chemical equation for this? we have benzene, so that's c6, h6, then we have oxygen gas, this is combustion, and then products are co2 and h2o.
00:21
So to balance this, we'll write here 6 and then here 3.
00:27
So that means you have a total of 15 oxygen on the right side.
00:32
So right here, 15 over 2.
00:34
So that's the balanced equation.
00:36
This is our answer.
00:38
First question.
00:39
Next one.
00:41
We're calculating the mass of co2.
00:46
So first let's calculate the number of moles of c6h6.
00:51
If we have 2 .0 liters, convert this to ml.
00:56
One liter is 1 ,000.
00:58
And then multiply the density 0 .8765 this grams per ml then divide the molar mass of c6h6 so that's 78 .112 grams then we have here moles so we cancel this and we'll get 22 .44 this is moles of benzene now let's calculate the mass of co2 if we have 22 .44, this is moles of c6h6.
01:39
One mole of c6h6 will be producing three moles of water as per our balance equation...