00:01
In this problem, we are asked to compare the heat transfer of the skin, the heat transfer of the muscle, and the heat transfer of the fat.
00:21
And so let's write down our equation for heat transfer.
00:25
Heat transfer is equal to our thermal conductivity of that substance, times the cross -sectional area, times the change in temperature, divided by the length or the depth.
00:36
And so from our table in the problem, we are given that q, or excuse me, k of the skin is equal to 0 .37 watts times kelvin.
01:00
K of the muscle is equal to 0 .41 watts per meter times kelvin.
01:10
And k of fat is equal to 0 .2 watts.
01:23
And so if we want to just compare our heat transfer of each q, let's see what our heat transfer is proportional to.
01:35
And so we can say in terms of direct proportionality, all we are given in this problem is our, or i guess all we really need to assess to really help us define this is our k or a delta t.
02:03
And regarding delta t, we are told that the change in temperature will be 2 degrees celsius.
02:12
Our change, or excuse me, our l will be equal to 5 millimeters.
02:19
And so we're also told that the area is the same for all fat, muscle, and skin, the cross -sectional area...